(x+5)(x+4)=x^2-9

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Solution for (x+5)(x+4)=x^2-9 equation: 



(x+5)(x+4)=x^2-9

We move all terms to the left:

(x+5)(x+4)-(x^2-9)=0

We get rid of parentheses

-x^2+(x+5)(x+4)+9=0

We multiply parentheses ..

-x^2+(+x^2+4x+5x+20)+9=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+4x+5x+20)+9=0

We get rid of parentheses

-1x^2+x^2+4x+5x+20+9=0

We add all the numbers together, and all the variables

9x+29=0

We move all terms containing x to the left, all other terms to the right

9x=-29

x=-29/9

x=-3+2/9

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